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the table shows the estimated number of lines of code written by comput…

Question

the table shows the estimated number of lines of code written by computer programmers per hour when x people are working. which model best represents the data?
productivity
people working lines of code written hourly
2 50
4 110
6 160
8 210
10 270
12 320
$y = 47(1.191)^x$
$y = 34(1.204)^x$
$y = 26.9x - 1.3$
$y = 27x - 4$

Explanation:

Step1: Check linear models

For a linear model \(y = mx + b\), the slope \(m=\frac{y_2 - y_1}{x_2 - x_1}\).
Take \(x_1 = 2,y_1 = 50\) and \(x_2=4,y_2 = 110\). Then \(m=\frac{110 - 50}{4 - 2}=\frac{60}{2}=30\).
For \(y = 26.9x-1.3\), when \(x = 2\), \(y=26.9\times2-1.3=53.8 - 1.3 = 52.5
eq50\).
For \(y = 27x-4\), when \(x = 2\), \(y=27\times2-4=54 - 4=50\). When \(x = 4\), \(y=27\times4-4=108 - 4 = 104
eq110\).

Step2: Check exponential models \(y = a\cdot b^x\)

For \(y = 47(1.191)^x\), when \(x = 2\), \(y=47\times(1.191)^2=47\times1.418481\approx66.67
eq50\).
For \(y = 34(1.204)^x\), when \(x = 2\), \(y = 34\times(1.204)^2=34\times1.449616\approx49.29\approx50\). When \(x=4\), \(y=34\times(1.204)^4\). \((1.204)^2\approx1.4496\), \((1.204)^4=(1.204)^2\times(1.204)^2\approx1.4496\times1.4496\approx2.10\), \(y = 34\times2.10 = 71.4
eq110\). But if we calculate more accurately: \((1.204)^4=1.204\times1.204\times1.204\times1.204=(1.204^2)^2=(1.449616)^2\approx2.101\), \(y=34\times2.101 = 71.434
eq110\). Wait, actually, if we consider the general trend.
Let's use another approach. Assume \(x = 2,y = 50\); \(x=4,y = 110\); \(x = 6,y = 160\).
The ratio for exponential \(r=\frac{y_2}{y_1}\) (for \(x_2=x_1 + 2\)). \(\frac{110}{50}=2.2\), \(\frac{160}{110}\approx1.45\) (not a constant ratio for exponential). But if we check the differences: \(110 - 50=60\), \(160 - 110 = 50\), \(210-160 = 50\), \(270 - 210=60\), \(320 - 270 = 50\). Wait, no, actually, if we calculate the slope more accurately for linear.
Take \(x_1=2,y_1 = 50\); \(x_2 = 12,y_2=320\). Slope \(m=\frac{320 - 50}{12 - 2}=\frac{270}{10}=27\). Then \(y-50=27(x - 2)\), \(y=27x-54 + 50=27x - 4\). When \(x = 4\), \(y=27\times4-4=108 - 4=104\) (there is some error due to data approximation, but compared to other models)

Answer:

\(y = 27x-4\)