Question

the table gives a set of outcomes and their probabilities. let a be the event \the outcome is less than or equal to 5\. find p(a).

outcome	probability
2	0.02
3	0.06
4	0.03
5	0.24
6	0.03
7	0.25
8	0.24
9	0.05

Explanation:

Step1: Identify relevant probabilities

Event \(A\) is outcome \(\leq5\). So we take probabilities of \(1,2,3,4,5\).
\(P(1) = 0.08\), \(P(2)=0.02\), \(P(3)=0.06\), \(P(4) = 0.03\), \(P(5)=0.24\)

Step2: Sum the probabilities

\(P(A)=P(1)+P(2)+P(3)+P(4)+P(5)\)
\(P(A)=0.08 + 0.02+0.06 + 0.03+0.24\)
\(P(A)=0.43\)

Answer:

\(0.43\)