Question

the table below gives the probability density of taffies in a bag. if a taffy is selected at random, what is the probability that it is a vanilla or banana? finally, find the probability of either taffy. p(a or b)=p(a)+p(b) p(vanilla)=0.31 p(banana)=0.21 p(vanilla or banana)=?

Explanation:

Step1: Apply the formula for \(P(A\ or\ B)\)

Given \(P(A\ or\ B)=P(A)+P(B)\), where \(A\) is the event of selecting vanilla taffy and \(B\) is the event of selecting banana taffy.

Step2: Substitute the values

Substitute \(P(\text{vanilla}) = 0.31\) and \(P(\text{banana})=0.21\) into the formula.
\(P(\text{vanilla or banana})=0.31 + 0.21\)

Step3: Calculate the sum

\(0.31+0.21 = 0.52\)

Answer:

\(0.52\)