Question

svlc algebra 1a - standard (15260)
solving systems of linear equations: substitution
what is the solution to the system of equations?
y = -3x - 2
5x + 2y = 15
(-40, 19) (19, -40) (-19, 55)
(55, -19)

Explanation:

Step1: Substitute \( y = -3x - 2 \) into \( 5x + 2y = 15 \)

Substitute the expression for \( y \) from the first equation into the second equation. So we get \( 5x + 2(-3x - 2) = 15 \).

Step2: Simplify the equation

Expand and simplify the left - hand side:

$$
LATEXBLOCK0
$$

Step3: Solve for \( x \)

Add 4 to both sides of the equation: \( -x=15 + 4=19 \), then multiply both sides by - 1 to get \( x=-19 \).

Step4: Solve for \( y \)

Substitute \( x = - 19 \) into \( y=-3x - 2 \):

$$
LATEXBLOCK1
$$

Answer:

\((-19, 55)\)