suppose $ \triangle def \cong \triangle mno $
which congruency statement is true?
$ \overline { e f } \cong \overline { m n } $
$ \overline { d e } \cong \overline { m n } $
$ \overline { d f } \cong \overline { n o } $
$ \overline { e f } \cong \overline { m o } $

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# Explanation:
## Step1: Recall the property of congruent triangles
When $\triangle DEF\cong\triangle MNO$, the corresponding parts are congruent. That is $DE = MN$, $EF=NO$, $DF = MO$, $\angle D=\angle M$, $\angle E=\angle N$, $\angle F=\angle O$

## Step2: Check each option
- For $\overline{EF}\cong\overline{MN}$: Since $EF = NO$ (from $\triangle DEF\cong\triangle MNO$), this is false.
- For $\overline{DE}\cong\overline{MN}$:  Since $DE = MN$ (from $\triangle DEF\cong\triangle MNO$), this is true.
- For $\overline{DF}\cong\overline{NO}$: Since $DF = MO$ (from $\triangle DEF\cong\triangle MNO$), this is false.
- For $\overline{EF}\cong\overline{MO}$: Since $EF = NO$ (from $\triangle DEF\cong\triangle MNO$), this is false.

# Answer:
$\overline{DE}\cong\overline{MN}$

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QUESTION IMAGE

Question

Explanation:

Step1: Recall the property of congruent triangles

Step2: Check each option

Answer: