Question

suppose a parallelogram is drawn on a coordinate plane. using the vertices with the coordinates (2,1), (2,3), (4,4), and (4,2), compute the perimeter. round your answer to the nearest tenth. (1 point) the perimeter is approximately \\(\square\\) units.

Explanation:

Step1: Calculate length of vertical side

Use distance formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. For (2,1) & (2,3): $d=\sqrt{(2-2)^2+(3-1)^2}=2$.

Step2: Calculate length of slant side

For (2,3) & (4,4): $d=\sqrt{(4-2)^2+(4-3)^2}=\sqrt{4+1}=\sqrt{5}\approx2.236$.

Step3: Compute perimeter

Perimeter = $2\times(vertical + slant)=2\times(2+2.236)=8.472$.

Step4: Round to nearest tenth

$8.472\approx8.5$.

Answer:

8.5