QUESTION IMAGE
Question
- is the sum of the areas of two smaller squares equal to the area of a large square if the side - lengths of the squares are 8 feet, 4 feet, and 3 feet? note that the area of a square is s², where s is the side - length. explain.
- lexi bought a new car. she drove 5² miles in the first month that she owned the car and 4² miles in the second month that she owned the car. how many miles did lexi drive in all during the first two months that she owned the car?
- communicate and justify. is 0.3⁴ equal to 0.9? explain.
- what are two ways that you can represent 27 using 3?
Response
- For the problem about the areas of squares:
- # Explanation:
- ## Step1: Calculate the area of the first - smaller square
- The side - length of the first smaller square is \(s_1 = 8\) feet. Using the formula \(A = s^{2}\), the area \(A_1=s_1^{2}=8^{2}=64\) square feet.
- ## Step2: Calculate the area of the second - smaller square
- The side - length of the second smaller square is \(s_2 = 3\) feet. Using the formula \(A = s^{2}\), the area \(A_2=s_2^{2}=3^{2}=9\) square feet.
- ## Step3: Calculate the sum of the areas of the two smaller squares
- \(A = A_1+A_2=64 + 9=73\) square feet. Let the side - length of the large square be \(s\). Then \(s^{2}=73\), and \(s=\sqrt{73}\approx8.54\) feet.
- # Answer: The side - length of the large square is \(\sqrt{73}\approx8.54\) feet.
- For the problem about Lexi's driving distance:
- # Explanation:
- ## Step1: Calculate the distance driven in the first month
- Lexi drove \(5^{2}\) miles in the first month. Since \(5^{2}=25\) miles.
- ## Step2: Calculate the distance driven in the second month
- Lexi drove \(4^{2}\) miles in the second month. Since \(4^{2}=16\) miles.
- ## Step3: Calculate the total distance driven in the first two months
- The total distance \(d=5^{2}+4^{2}=25 + 16=41\) miles.
- # Answer: 41 miles
- For the problem about \(0.3^{4}\) and \(0.09^{2}\):
- # Explanation:
- ## Step1: Calculate \(0.3^{4}\)
- \(0.3^{4}=0.3\times0.3\times0.3\times0.3=(0.3\times0.3)\times(0.3\times0.3)=0.09\times0.09 = 0.0081\).
- ## Step2: Calculate \(0.09^{2}\)
- \(0.09^{2}=0.09\times0.09 = 0.0081\).
- So \(0.3^{4}=0.09^{2}\) because \(0.3^{4}=(0.3\times0.3)\times(0.3\times0.3)=0.09\times0.09 = 0.09^{2}\).
- # Answer: Yes, \(0.3^{4}\) is equal to \(0.09^{2}\) because \(0.3^{4}=(0.3\times0.3)\times(0.3\times0.3)=0.09\times0.09 = 0.09^{2}\).
- For the problem about representing 27 using 3:
- # Explanation:
- ## Step1: First way
- \(3^{3}=3\times3\times3 = 27\).
- ## Step2: Second way
- \(3\times9=27\), and since \(9 = 3\times3\), we can write \(27=3\times(3\times3)\).
- # Answer: \(3^{3}\) and \(3\times(3\times3)\)
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- For the problem about the areas of squares:
- # Explanation:
- ## Step1: Calculate the area of the first - smaller square
- The side - length of the first smaller square is \(s_1 = 8\) feet. Using the formula \(A = s^{2}\), the area \(A_1=s_1^{2}=8^{2}=64\) square feet.
- ## Step2: Calculate the area of the second - smaller square
- The side - length of the second smaller square is \(s_2 = 3\) feet. Using the formula \(A = s^{2}\), the area \(A_2=s_2^{2}=3^{2}=9\) square feet.
- ## Step3: Calculate the sum of the areas of the two smaller squares
- \(A = A_1+A_2=64 + 9=73\) square feet. Let the side - length of the large square be \(s\). Then \(s^{2}=73\), and \(s=\sqrt{73}\approx8.54\) feet.
- # Answer: The side - length of the large square is \(\sqrt{73}\approx8.54\) feet.
- For the problem about Lexi's driving distance:
- # Explanation:
- ## Step1: Calculate the distance driven in the first month
- Lexi drove \(5^{2}\) miles in the first month. Since \(5^{2}=25\) miles.
- ## Step2: Calculate the distance driven in the second month
- Lexi drove \(4^{2}\) miles in the second month. Since \(4^{2}=16\) miles.
- ## Step3: Calculate the total distance driven in the first two months
- The total distance \(d=5^{2}+4^{2}=25 + 16=41\) miles.
- # Answer: 41 miles
- For the problem about \(0.3^{4}\) and \(0.09^{2}\):
- # Explanation:
- ## Step1: Calculate \(0.3^{4}\)
- \(0.3^{4}=0.3\times0.3\times0.3\times0.3=(0.3\times0.3)\times(0.3\times0.3)=0.09\times0.09 = 0.0081\).
- ## Step2: Calculate \(0.09^{2}\)
- \(0.09^{2}=0.09\times0.09 = 0.0081\).
- So \(0.3^{4}=0.09^{2}\) because \(0.3^{4}=(0.3\times0.3)\times(0.3\times0.3)=0.09\times0.09 = 0.09^{2}\).
- # Answer: Yes, \(0.3^{4}\) is equal to \(0.09^{2}\) because \(0.3^{4}=(0.3\times0.3)\times(0.3\times0.3)=0.09\times0.09 = 0.09^{2}\).
- For the problem about representing 27 using 3:
- # Explanation:
- ## Step1: First way
- \(3^{3}=3\times3\times3 = 27\).
- ## Step2: Second way
- \(3\times9=27\), and since \(9 = 3\times3\), we can write \(27=3\times(3\times3)\).
- # Answer: \(3^{3}\) and \(3\times(3\times3)\)