Question

study guide: work, potential energy, kinetic energy. quiz thursday, 12/11

1. define

a. potential energy
b. kinetic energy
part 1: this graph shows a ball rolling from a to g.
(image of a balls path with points a - g)
2.
a. which letter shows the ball when it has maximum kinetic energy?
b. which letter shows the ball when it has the least potential energy?
c. which letter shows the ball when it has the least kinetic energy?
d. which letter shows the ball when it has the maximum potential energy?

1. what is the relationship between potential energy and kinetic energy?
2. 3. a car is traveling with a velocity of 50.3 m/s and has a mass of 1320 kg. the car has

______ energy.
calculate it.

1. a cinder block is sitting on a platform 200 m high. it weighs 17.9 kg. the block has

______ energy.
calculate it.

1. angela uses a force of 200 newtons to lift her grocery bag while doing 50 joules of w

how far did she lift the grocery bags?

1. the baseball player does 1500 joules of work when hitting a baseball into left field.

assuming the baseball landed 120 meters away from home plate, how much force did
the player use to hit the ball?

1. sketch a graph that shows the amount of work done on a cart of the same mass at

different angles of a ramp that reach the same height.

1. sketch a graph that shows the amount of force done on a cart of the same mass at

different angles of a ramp that reach the same height.

Explanation:

Step1: Recall Kinetic Energy Formula

Kinetic Energy (KE) is given by the formula \( KE = \frac{1}{2}mv^2 \), where \( m \) is mass and \( v \) is velocity.

Step2: Identify Given Values

Mass \( m = 1320 \, \text{kg} \), velocity \( v = 50.3 \, \text{m/s} \).

Step3: Substitute Values into Formula

\( KE = \frac{1}{2} \times 1320 \times (50.3)^2 \)
First, calculate \( (50.3)^2 = 50.3 \times 50.3 = 2530.09 \)
Then, \( \frac{1}{2} \times 1320 = 660 \)
Now, multiply \( 660 \times 2530.09 = 1669859.4 \)

Answer:

The kinetic energy of the car is \( 1669859.4 \, \text{Joules} \) (or \( 1.67 \times 10^6 \, \text{J} \) approximately).