Question

a student connects four aa batteries (each battery is 1.5 volts) in series to light up a light bulb. the circuit has a resistance of 6ω. how much current flows through the circuit?
a 1a
b 75a
c 0.03a
d 300a

Explanation:

Step1: Calculate total voltage

When batteries are in series, total voltage \(V = n\times V_{single}\). Here \(n = 4\) (number of batteries) and \(V_{single}=1.5\ V\). So \(V=4\times1.5\ V = 6\ V\).

Step2: Use Ohm's law \(I=\frac{V}{R}\)

Given \(R = 6\ \Omega\) and \(V = 6\ V\). Then \(I=\frac{6\ V}{6\ \Omega}=1\ A\).

Answer:

A. 1A