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a student arrives 10 minutes early to class every day for 4 days. how m…

Question

a student arrives 10 minutes early to class every day for 4 days. how many minutes early must the student arrive on the 5th day so that, over the 5 - day period, they arrive 15 minutes early on average?

Explanation:

Step1: Calculate total minutes early for 4 - day period

The student arrives 10 minutes early each day for 4 days. Using the formula \(total = number\times amount\), we have \(10\times4 = 40\) minutes.

Step2: Calculate total minutes early for 5 - day period

The average for 5 days is 15 minutes early. Using the formula \(total = average\times number\), we get \(15\times5=75\) minutes.

Step3: Find minutes early on the 5th day

Let \(x\) be the minutes early on the 5th day. Then \(40 + x=75\). Solving for \(x\), we subtract 40 from both sides: \(x = 75-40\).

Answer:

\(35\)