QUESTION IMAGE
Question
statements reasons 1. r ∥ s given 2. ( m_r = \frac{d - b}{c - 0} = \frac{d - b}{c} ) ( m_s = \frac{0 - a}{c - 0} = -\frac{a}{c} ) application of the slope formula 3. distance from (0, b) to (0, a) equals the distance from (c, d) to (c, 0) definition of parallel lines 4.? application of the distance formula 5. ( m_r = \frac{(b - a) - b}{c} ) substitution property of equality 6. ( m_r = -\frac{a}{c} ) inverse property of addition 7. ( m_r = m_s ) substitution property of equality the table and corresponding image show the proof of the relationship between the slopes of two parallel lines. what is the missing statement in step 4? a. ( c - 0 = a - b ) b. ( d - 0 = b - a ) c. ( c - d = b - a ) d. ( b - c = d - a )
Step1: Recall Distance Formula
The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). For vertical segments (same \(x\)-coordinate), the distance is \(|y_2 - y_1|\).
Step2: Analyze Distances
- Distance from \((0,b)\) to \((0,a)\): Since \(x\)-coordinates are 0, distance is \(|b - a|=|a - b|\) (absolute value, but for equality, we can consider \(b - a\) or \(a - b\) with sign depending on direction, but here we use the formula result).
- Distance from \((c,d)\) to \((c,0)\): \(x\)-coordinates are \(c\), so distance is \(|d - 0|=|d|\)? Wait, no, wait. Wait, the vertical distance: for \((0,b)\) to \((0,a)\), the change in \(y\) is \(b - a\) (if \(b>a\)) or \(a - b\) (if \(a>b\)), but the distance is \(|b - a|\). For \((c,d)\) to \((c,0)\), the change in \(y\) is \(d - 0=d\)? No, wait, no—wait, the problem says "distance from \((0,b)\) to \((0,a)\) equals the distance from \((c,d)\) to \((c,0)\)". So applying distance formula:
For \((0,b)\) to \((0,a)\): \(d_1=\sqrt{(0 - 0)^2+(a - b)^2}=|a - b|\) (or \(|b - a|\)).
For \((c,d)\) to \((c,0)\): \(d_2=\sqrt{(c - c)^2+(0 - d)^2}=|d - 0|=|d|\)? Wait, no, that can't be. Wait, maybe I misread the points. Wait, step 3 says "distance from \((0,b)\) to \((0,a)\) equals the distance from \((c,d)\) to \((c,0)\)". So let's compute both distances:
Distance 1 (vertical line \(x = 0\)): between \((0,b)\) and \((0,a)\): \(y\)-difference is \(a - b\) (so distance is \(|a - b|\)).
Distance 2 (vertical line \(x = c\)): between \((c,d)\) and \((c,0)\): \(y\)-difference is \(0 - d=-d\) (or \(d - 0=d\)), distance is \(|d - 0|=|d|\)? No, that's not matching. Wait, maybe the points are \((0,b)\) to \((0,a)\): the vertical distance is \(b - a\) (if we consider direction, but the distance formula gives \(\sqrt{(0 - 0)^2+(a - b)^2}=|a - b|\)). For \((c,d)\) to \((c,0)\): \(\sqrt{(c - c)^2+(0 - d)^2}=|d - 0|=|d|\). But that doesn't seem to connect. Wait, no—wait, maybe the problem has a typo? Wait, no, looking at step 5: \(m_r=\frac{(b - a)-b}{c}\)? Wait, no, step 5 is \(m_r=\frac{(b - a)-b}{c}\)? Wait, no, step 5 is \(m_r=\frac{(b - a)-b}{c}\)? Wait, no, let's look at the slope of \(r\): \(m_r=\frac{d - b}{c}\) (from step 2). Then step 5 substitutes something. Wait, the distance from \((0,b)\) to \((0,a)\) is \(|b - a|\), and from \((c,d)\) to \((c,0)\) is \(|d - 0|=|d|\)? No, that's not. Wait, maybe the vertical distance is \(b - a\) (if \(b\) is above \(a\)) and \(d - 0=d\), but that would mean \(b - a=d\)? No, that's not. Wait, no—wait, the distance formula application in step 4: so the distance from \((0,b)\) to \((0,a)\) is \(|b - a|\), and from \((c,d)\) to \((c,0)\) is \(|d - 0|=|d|\)? No, that's not. Wait, maybe the points are \((0,b)\) to \((0,a)\): the change in \(y\) is \(a - b\) (so distance is \(|a - b|\)), and from \((c,d)\) to \((c,0)\): change in \(y\) is \(0 - d=-d\), so distance is \(|d|\). But that doesn't fit. Wait, maybe I made a mistake. Wait, let's look at the answer options.
Option B: \(d - 0=b - a\). Let's check: distance from \((0,b)\) to \((0,a)\) is \(|b - a|\) (using distance formula: \(\sqrt{(0 - 0)^2+(a - b)^2}=|a - b|\)). Distance from \((c,d)\) to \((c,0)\) is \(\sqrt{(c - c)^2+(0 - d)^2}=|d - 0|=|d|\). But if we apply the distance formula (without absolute value for the expression, considering the actual difference), then:
For \((0,b)\) to \((0,a)\): distance is \(|b - a|=b - a\) (assuming \(b>a\)) or \(a - b\) (if \(a>b\)). For \((c,d)\) to \((c,0)\): distance is \(|d - 0|=d\) (if \(d>0\)) or \(-d\) (if \(…
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
B. \( d - 0 = b - a \)