Question

1. $-5x + y = 5$

standard form $x$-intercept $y$-intercept
$ax = c$ $by = c$

intercept = ( ) intercept = ( )

Explanation:

Step1: Find x-intercept (set y=0)

Set \( y = 0 \) in \( -5x + y = 5 \), we get \( -5x + 0 = 5 \), which simplifies to \( -5x = 5 \). Then divide both sides by -5: \( x = \frac{5}{-5} = -1 \). So the x-intercept is \( (-1, 0) \).

Step2: Find y-intercept (set x=0)

Set \( x = 0 \) in \( -5x + y = 5 \), we get \( -5(0) + y = 5 \), which simplifies to \( y = 5 \). So the y-intercept is \( (0, 5) \).

Step3: Standard Form (Ax + By = C)

The given equation \( -5x + y = 5 \) is already in standard form where \( A = -5 \), \( B = 1 \), \( C = 5 \). For x-intercept form (Ax = C), we can rewrite it as \( -5x = 5 \) (by subtracting y from both sides, but since we set y=0 for x-intercept, the x-intercept equation is \( -5x = 5 \)). For y-intercept form (By = C), we rewrite it as \( 1y = 5 \) (since when x=0, \( y = 5 \)).

Answer:

Standard Form: \( -5x + y = 5 \)
x - intercept (Ax = C): \( -5x = 5 \), intercept point: \( (-1, 0) \)
y - intercept (By = C): \( y = 5 \), intercept point: \( (0, 5) \)