Question

square wxyz with vertices w(1,7). x(6,5). y(4,0), and z(-1,2): (x,y)→(x - 7,y) w (__,) y (,) x (,) z (,__)

Explanation:

Step1: Apply the transformation to point \(W(1,7)\)

The transformation is \((x,y)\to(x - 7,y)\). For \(W(1,7)\), substitute \(x = 1\) and \(y=7\) into the transformation formula.
\(x'=1-7=-6\), \(y' = 7\). So \(W'(-6,7)\)

Step2: Apply the transformation to point \(X(6,5)\)

Substitute \(x = 6\) and \(y = 5\) into \((x,y)\to(x - 7,y)\).
\(x'=6 - 7=-1\), \(y'=5\). So \(X'(-1,5)\)

Step3: Apply the transformation to point \(Y(4,0)\)

Substitute \(x = 4\) and \(y = 0\) into \((x,y)\to(x - 7,y)\).
\(x'=4-7=-3\), \(y'=0\). So \(Y'(-3,0)\)

Step4: Apply the transformation to point \(Z(-1,2)\)

Substitute \(x=-1\) and \(y = 2\) into \((x,y)\to(x - 7,y)\).
\(x'=-1-7=-8\), \(y'=2\). So \(Z'(-8,2)\)

Answer:

\(W'(-6,7)\), \(Y'(-3,0)\), \(X'(-1,5)\), \(Z'(-8,2)\)