Question

1. in the square below, if wy = 32, find xy. round to the nearest tenth.

xy = \square

Explanation:

Step1: Identify square diagonal property

Diagonals of square are equal: $WY = XZ = 32$

Step2: Relate diagonal to side length

For square, diagonal $d = s\sqrt{2}$, so $s = \frac{d}{\sqrt{2}}$

Step3: Calculate side length XY

$XY = \frac{32}{\sqrt{2}} = 16\sqrt{2} \approx 22.6$

Answer:

22.6