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Question
speed and velocity quiz complete ingrid is participating in a relay race. while jogging at 9 km/h, she tosses a relay stick at 16 km/h to her teammate, who is standing still. how fast is the relay stick moving relative to ingrid? 8 km/h 9 km/h 16 km/h 25 km/h
Step1: Analyze the motion of Ingrid and the relay - stick
Ingrid is jogging at a speed \(v_{Ingrid}=9\ km/h\) and she tosses the relay - stick at a speed \(v_{stick}=16\ km/h\) relative to the ground.
Step2: Calculate the relative speed
The relative speed of the relay - stick with respect to Ingrid \(v_{rel}\) is calculated using the formula \(v_{rel}=v_{stick}-v_{Ingrid}\) (since they are moving in the same direction). Substitute \(v_{Ingrid} = 9\ km/h\) and \(v_{stick}=16\ km/h\) into the formula: \(v_{rel}=16 - 9\).
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\(7\ km/h\) (It seems there is a mistake in the provided options. If we assume the direction of motion is considered correctly, and using the formula for relative velocity \(v = v_{object}-v_{observer}\), when Ingrid is the observer (\(v_{observer}=9\ km/h\)) and the stick's velocity with respect to the ground \(v_{object} = 16\ km/h\), the relative velocity \(v=16 - 9=7\ km/h\). But if we consider a wrong approach of adding (which is incorrect for the same - direction motion), there is no correct option. If we assume a mis - statement in the problem (e.g., if the stick is thrown in the opposite direction of Ingrid's motion, \(v_{rel}=16+9 = 25\ km/h\), but the problem says "to her teammate who is standing still" which implies the same general direction as Ingrid's motion towards the teammate. However, if we follow the wrong addition approach (which is not in line with relative - motion principles for same - direction), the closest wrong - calculation - based answer from the given options is \(16\ km/h\) (if we ignore Ingrid's motion, which is wrong), but the correct physical - principle - based answer is \(7\ km/h\) (not in the options). If we assume a typo in the problem setup and use addition (wrong method), the answer is \(25\ km/h\))