Question

in some plants, red flowers are dominant (r) and white flowers are recessive (r). two plants are crossed and the offspring have a possibility of 3/4 red flowers and 1/4 white flowers. which punnett square shows the cross and its offspring?

Explanation:

Step1: Recall Punnett - square principles

The probability of white flowers (recessive, rr) is $\frac{1}{4}$. According to the Punnett - square method, when two heterozygous individuals (Rr) are crossed, the possible genotypes of the offspring are determined by the combination of alleles from each parent.

Step2: Analyze the cross of Rr x Rr

When we cross Rr x Rr, the possible gametes from each parent are R and r. Using a Punnett - square, we have the following combinations: RR:Rr:Rr:rr in a 1:2:1 ratio. The probability of rr (white flowers) is $\frac{1}{4}$ and the probability of having at least one R allele (red flowers) is $\frac{3}{4}$.

Answer:

The Punnett - square with parents Rr and Rr (where one parent has alleles R and r along the top and the other has alleles R and r along the side, resulting in genotypes RR, Rr, Rr, rr in the four - box square) shows the cross and its offspring.