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solving real - world problems (volume of cylinders) if the radius of a …

Question

solving real - world problems (volume of cylinders) if the radius of a cylinder is doubled, how does the volume change? a. it doubles. b. it halves. c. it stays the same. d. it quadruples. which of the following is not component of a cylinder? a. height b. circular base c. radius d. triangular base

Explanation:

Step1: Recall volume formula

The volume formula of a cylinder is $V = \pi r^{2}h$, where $r$ is the radius and $h$ is the height.

Step2: Double the radius

Let the new radius be $r'=2r$. Then the new volume $V'=\pi(2r)^{2}h = 4\pi r^{2}h$.

Step3: Compare volumes

We can see that $V' = 4V$, so the volume quadruples.

For the second - question:
A cylinder has a circular base and a height. The radius is related to the circular base. A cylinder does not have a triangular base.

Answer:

  1. d. It quadruples.
  2. d. Triangular base