Question

solve using substitution.
$y = 2x + 4$
$y = -x - 8$
$(square, square)$

Explanation:

Step1: Substitute y from first equation

Since \( y = 2x + 4 \) and \( y = -x - 8 \), substitute \( y \) in the second equation with \( 2x + 4 \):
\( 2x + 4 = -x - 8 \)

Step2: Solve for x

Add \( x \) to both sides: \( 3x + 4 = -8 \)
Subtract 4 from both sides: \( 3x = -12 \)
Divide by 3: \( x = -4 \)

Step3: Find y using x

Substitute \( x = -4 \) into \( y = 2x + 4 \):
\( y = 2(-4) + 4 = -8 + 4 = -4 \)

Answer:

\((-4, -4)\)