Question

solve using substitution.
$y = 6x + 1$
$y = 8x + 3$
(\square, \square)

Explanation:

Step1: Substitute y from first equation

Since \( y = 6x + 1 \) and \( y = 8x + 3 \), substitute \( y \) in the second equation: \( 6x + 1 = 8x + 3 \)

Step2: Solve for x

Subtract \( 6x \) from both sides: \( 1 = 2x + 3 \)
Subtract 3 from both sides: \( -2 = 2x \)
Divide by 2: \( x = -1 \)

Step3: Find y using x

Substitute \( x = -1 \) into \( y = 6x + 1 \): \( y = 6(-1) + 1 = -6 + 1 = -5 \)

Answer:

\((-1, -5)\)