Question

solve the system by substitution.
3x + 4y = -6
x = 5y - 2
the solution is (\square, \square).

Explanation:

Step1: Substitute \( x = 5y - 2 \) into \( 3x + 4y = -6 \)

Substitute \( x \) in the first equation with \( 5y - 2 \), we get:
\( 3(5y - 2) + 4y = -6 \)

Step2: Simplify and solve for \( y \)

Expand the left - hand side:
\( 15y-6 + 4y=-6 \)
Combine like terms:
\( 19y-6=-6 \)
Add 6 to both sides:
\( 19y=-6 + 6=0 \)
Divide both sides by 19:
\( y = 0 \)

Step3: Substitute \( y = 0 \) into \( x = 5y - 2 \) to find \( x \)

Substitute \( y = 0 \) into \( x = 5y-2 \), we have:
\( x=5\times0 - 2=-2 \)

Answer:

\((-2,0)\)