Question

solve the system of equations.
3x + 4y = -23
x = 3y + 1
x =

y =

Explanation:

Step1: Substitute x in first equation

Substitute $x = 3y + 1$ into $3x+4y=-23$. We get $3(3y + 1)+4y=-23$.

Step2: Expand the left - hand side

Expand $3(3y + 1)$ to get $9y+3$. So the equation becomes $9y + 3+4y=-23$.

Step3: Combine like terms

Combine $9y$ and $4y$ on the left - hand side: $(9y + 4y)+3=-23$, which simplifies to $13y+3=-23$.

Step4: Isolate the term with y

Subtract 3 from both sides: $13y=-23 - 3$, so $13y=-26$.

Step5: Solve for y

Divide both sides by 13: $y=\frac{-26}{13}=-2$.

Step6: Solve for x

Substitute $y = - 2$ into $x = 3y+1$. Then $x=3\times(-2)+1=-6 + 1=-5$.

Answer:

$x=-5$, $y=-2$