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solve the system of equations. -4x + 3y = -2 y = x - 1 x = 1, y = 0 sho…

Question

solve the system of equations.
-4x + 3y = -2
y = x - 1
x = 1,
y = 0
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systems of equations with substitution: -3x -4y = -2 & y = 2

Explanation:

Step1: Substitute \( y = x - 1 \) into \( -4x + 3y = -2 \)

Substitute \( y \) in the first equation: \( -4x + 3(x - 1) = -2 \)

Step2: Simplify the equation

Expand and combine like terms: \( -4x + 3x - 3 = -2 \) → \( -x - 3 = -2 \)

Step3: Solve for \( x \)

Add 3 to both sides: \( -x = 1 \) → Multiply by -1: \( x = -1 \) (Wait, original input had x=1, but let's recalculate. Wait, correct substitution: \( -4x + 3(x - 1) = -4x + 3x - 3 = -x - 3 = -2 \). Then \( -x = 1 \) → \( x = -1 \). Then \( y = x - 1 = -1 - 1 = -2 \). Wait, maybe the original input's filled values were wrong. Let's do it correctly.

Wait, let's redo:

Equation 1: \( -4x + 3y = -2 \)

Equation 2: \( y = x - 1 \)

Substitute equation 2 into equation 1:

\( -4x + 3(x - 1) = -2 \)

\( -4x + 3x - 3 = -2 \)

\( -x - 3 = -2 \)

Add 3 to both sides: \( -x = 1 \) → \( x = -1 \)

Then \( y = x - 1 = -1 - 1 = -2 \)

Wait, maybe the user's initial filled values were incorrect. Let's solve properly.

Step1: Substitute \( y = x - 1 \) into \( -4x + 3y = -2 \)

\( -4x + 3(x - 1) = -2 \)

Step2: Expand and simplify

\( -4x + 3x - 3 = -2 \) → \( -x - 3 = -2 \)

Step3: Solve for \( x \)

\( -x = -2 + 3 \) → \( -x = 1 \) → \( x = -1 \)

Step4: Solve for \( y \)

Substitute \( x = -1 \) into \( y = x - 1 \): \( y = -1 - 1 = -2 \)

Wait, but the original problem's filled boxes had x=1, y=0, which is incorrect. Let's check with x=1, y=0:

Plug into first equation: \( -4(1) + 3(0) = -4
eq -2 \). So wrong. Correct solution:

Answer:

\( x = -1 \), \( y = -2 \)

Wait, maybe the original equation was \( -4x + 3y = -2 \) and \( y = x - 1 \). Let's verify:

For \( x = -1 \), \( y = -2 \):

\( -4(-1) + 3(-2) = 4 - 6 = -2 \), which matches. And \( y = -1 - 1 = -2 \), correct.

So the correct solution is \( x = -1 \), \( y = -2 \)