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solve the quadratic equation. $-x^{2}+2x - 2 = 0$ write one exact solut…

Question

solve the quadratic equation.
$-x^{2}+2x - 2 = 0$
write one exact solution in each box. you can add or remove boxes. if there
are no real solutions, remove all boxes.

Explanation:

Step1: Multiply by -1 to simplify

Multiply the equation \(-x^2 + 2x - 2 = 0\) by \(-1\) to get \(x^2 - 2x + 2 = 0\).

Step2: Identify coefficients

For the quadratic equation \(ax^2 + bx + c = 0\), here \(a = 1\), \(b = -2\), \(c = 2\).

Step3: Calculate discriminant

The discriminant is \(D = b^2 - 4ac\). Substitute the values: \(D = (-2)^2 - 4\times1\times2 = 4 - 8 = -4\).

Step4: Analyze discriminant

Since \(D = -4 < 0\), the quadratic equation has no real solutions.

Answer:

(No real solutions, so no boxes with solutions)