Question

solve for x. (just put the number, not x = !!!!) *
your answer
solve for x. (just put the number, not x = !!!!) *
dz = 2x - 13
zf = x - 1

Explanation:

Step1: Use the property of parallelogram

In parallelogram \(RSTQ\), \(RS = QT\). Given \(RS = 10\) and \(QT=-6 + 2x\), we set up the equation \(10=-6 + 2x\).

Step2: Solve the equation for \(x\)

Add \(6\) to both sides of the equation: \(10 + 6=-6+6 + 2x\), which simplifies to \(16 = 2x\).
Divide both sides by \(2\): \(x=\frac{16}{2}=8\).

Step1: Use the property of parallelogram (diagonals bisect each other)

In parallelogram \(DECF\), \(DZ = ZF\). Given \(DZ = 2x-13\) and \(ZF=x - 1\), we set up the equation \(2x-13=x - 1\).

Step2: Solve the equation for \(x\)

Subtract \(x\) from both sides: \(2x-x-13=x-x - 1\), which gives \(x-13=-1\).
Add \(13\) to both sides: \(x-13 + 13=-1+13\), so \(x = 12\).

Answer:

8