Question

solve $x^2 = \frac{25}{64}$ by inspection. there are two real solutions. enter the lesser number first. leave the answers in simplest fraction form. (1 point)
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Explanation:

Step1: Recall square root property

If \(x^2 = a\) (where \(a\geq0\)), then \(x=\pm\sqrt{a}\). Here, \(a = \frac{25}{64}\).

Step2: Find square roots

We know that \(\sqrt{\frac{25}{64}}=\frac{\sqrt{25}}{\sqrt{64}}=\frac{5}{8}\) and \(-\sqrt{\frac{25}{64}}=-\frac{5}{8}\). Since \(-\frac{5}{8}<\frac{5}{8}\), the lesser number is \(-\frac{5}{8}\) and the other is \(\frac{5}{8}\).

Answer:

\(-\frac{5}{8}, \frac{5}{8}\)