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solve the inequality and graph the solution. \\frac{q + 8}{4} \\leq 3 p…

Question

solve the inequality and graph the solution.
\frac{q + 8}{4} \leq 3
plot the endpoints. select an endpoint to change it from closed to open. select the middle of the segment, ray, or line to delete it.

Explanation:

Step1: Multiply both sides by 4

$$\frac{g + 8}{4}\times4\leq3\times4$$
$$g + 8\leq12$$

Step2: Subtract 8 from both sides

$$g+8 - 8\leq12 - 8$$
$$g\leq4$$

To graph the solution:

  • The endpoint is at \(g = 4\). Since the inequality is \(\leq\), the endpoint is closed.
  • The graph is a ray starting at \(4\) and going to the left (towards the smaller numbers) on the number - line.

Answer:

The solution of the inequality is \(g\leq4\). On the number - line, we have a closed circle at \(4\) and a ray extending to the left.