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Question
solve the inequality and graph the solution on the line provided. -13 + 8x ≤ -45
Step1: Add 13 to both sides
$$-13 + 8x+13\leq -45 + 13$$
$$8x\leq - 32$$
Step2: Divide both sides by 8
$$\frac{8x}{8}\leq\frac{-32}{8}$$
$$x\leq - 4$$
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The solution of the inequality is \(x\leq - 4\). To graph it on a number line: draw a number line, put a closed circle at \(-4\) (because the inequality includes equality, \(\leq\)) and shade the line to the left of \(-4\) (since \(x\) is less than or equal to \(-4\)).