Question

solve and graph the solutions. 4x - 8 ≤ 0 or x + 6 ≥ 10

Explanation:

Step1: Solve \(4x - 8\leq0\)

Add \(8\) to both sides: \(4x\leq8\).
Divide both sides by \(4\): \(x\leq2\).

Step2: Solve \(x + 6\geq10\)

Subtract \(6\) from both sides: \(x\geq4\).

Answer:

The solution of the compound inequality \(4x - 8\leq0\) or \(x + 6\geq10\) is \(x\leq2\) or \(x\geq4\).

To graph:

• For \(x\leq2\), draw a closed circle at \(x = 2\) (since the inequality includes equality) and shade to the left.
• For \(x\geq4\), draw a closed circle at \(x = 4\) (since the inequality includes equality) and shade to the right.