Question

1. solve $10 + x \geq 14$. then graph the solution.
2. solve $-11 \leq x - 20$. then graph the solution.

Explanation:

Problem 8:

Step1: Isolate \( x \)

Subtract 10 from both sides of \( 10 + x \geq 14 \):
\( 10 + x - 10 \geq 14 - 10 \)
Simplify: \( x \geq 4 \)

Step2: Graph the solution

On a number line, draw a closed circle at 4 (since \( \geq \) includes 4) and shade to the right (for all values greater than or equal to 4).

Step1: Isolate \( x \)

Add 20 to both sides of \( -11 \leq x - 20 \):
\( -11 + 20 \leq x - 20 + 20 \)
Simplify: \( 9 \leq x \) or \( x \geq 9 \)

Step2: Graph the solution

On a number line, draw a closed circle at 9 (since \( \geq \) includes 9) and shade to the right (for all values greater than or equal to 9).

Answer:

\( x \geq 4 \) (Graph: Closed circle at 4, shade right)

Problem 9: