Question

solve for j and graph the solution. -9 > j - 3 ≥ -14 plot the endpoints. select an endpoint to change it from closed to open. select a segment, ray, or line to delete it.

Explanation:

Step1: Solve the left - hand inequality

Add \(3\) to both sides of \(-9>j - 3\).
\(-9+3>j-3 + 3\)
\(-6>j\) or \(j < - 6\)

Step2: Solve the right - hand inequality

Add \(3\) to both sides of \(j-3\geq - 14\).
\(j-3 + 3\geq-14 + 3\)
\(j\geq-11\)

Answer:

The solution of the inequality is \(-11\leq j<-6\). On the number line, we have a closed circle at \(-11\) (because \(j=-11\) is included in the solution, since the inequality is \(j\geq - 11\)) and an open circle at \(-6\) (because \(j = - 6\) is not included in the solution, since the inequality is \(j<-6\)), and the line segment between them.