Question

solve and graph the following inequality: 10 + 8x ≥ 2 + 3x

Explanation:

Step1: Move like - terms to one side

Subtract 3x from both sides and subtract 10 from both sides:
\[10 + 8x-3x - 10\geq2 + 3x-3x - 10\]
\[5x\geq - 8\]

Step2: Solve for x

Divide both sides by 5:
\[x\geq-\frac{8}{5}=-1.6\]

Answer:

Inequality: \(x\geq - 1.6\)
To graph: On a number - line, draw a closed circle at \(x = - 1.6\) (because the inequality is \(\geq\)) and shade to the right of \(x=-1.6\).