Question

solve the function.
$x^{3}+5x^{2}-3x - 15 = 0$
$x = ?,pmsqrt{}$
simplify your answer.

Explanation:

Step1: Group the terms

$(x^{3}+5x^{2})-(3x + 15)=0$

Step2: Factor out common factors from each group

$x^{2}(x + 5)-3(x + 5)=0$

Step3: Factor out the common binomial factor

$(x + 5)(x^{2}-3)=0$

Step4: Set each factor equal to zero

$x+5 = 0$ or $x^{2}-3=0$

Step5: Solve for x in $x + 5=0$

$x=-5$

Step6: Solve for x in $x^{2}-3=0$

$x^{2}=3$, so $x=\pm\sqrt{3}$

Answer:

$x=-5,\pm\sqrt{3}$