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Question
solve the following system of equations.
\\
\
$$\begin{aligned}
8x + 5y &= -2 \\\\
-3x - 7y &= 11
\\end{aligned}$$
\\
\\x = \square\\
\\y = \square\\
Set up the system of equations
$$
LATEXBLOCK0
$$
Eliminate x to solve for y
Multiply equation (1) by 3 and equation (2) by 8:
$$
LATEXBLOCK1
$$
Add the two equations:
$$
LATEXBLOCK2
$$
Substitute y back to solve for x
Substitute \(y = -2\) into equation (1):
$$
LATEXBLOCK3
$$
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Solve the following system of equations.
$$
LATEXBLOCK0
$$
\(x =\) <blank>1</blank>
\(y =\) <blank>-2</blank>