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solve for x for the following quadratic. note: it does not matter which…

Question

solve for x for the following quadratic. note: it does not matter which number you put first. (x - 9)(2x + 1) = 0 x = and x =

Explanation:

Step1: Apply zero - product property

If \((a)(b)=0\), then \(a = 0\) or \(b=0\). Here \(a=x - 9\) and \(b = 2x+1\).

Step2: Solve \(x - 9=0\)

Add 9 to both sides of the equation \(x-9 = 0\). We get \(x=9\).

Step3: Solve \(2x + 1=0\)

Subtract 1 from both sides: \(2x=-1\). Then divide both sides by 2, so \(x=-\frac{1}{2}\).

Answer:

\(x = 9\) and \(x=-\frac{1}{2}\)