Question

solve the following inequality: $30 + 3x \geq 30$

Explanation:

Step1: Subtract 30 from both sides

To isolate the term with \( x \), we subtract 30 from both sides of the inequality \( 30 + 3x \geq 30 \). This gives us \( 30 + 3x - 30 \geq 30 - 30 \), which simplifies to \( 3x \geq 0 \).

Step2: Divide both sides by 3

To solve for \( x \), we divide both sides of the inequality \( 3x \geq 0 \) by 3. Since 3 is a positive number, the direction of the inequality sign remains the same. So we have \( \frac{3x}{3} \geq \frac{0}{3} \), which simplifies to \( x \geq 0 \).

Answer:

\( x \geq 0 \)