Question

solve the following compound inequality.

\\-1 \le \frac{d + 2}{5} \le \frac{6}{5}\\

\\? \le d \le \quad\\

Explanation:

Multiply all parts by 5

$$ -1 \cdot 5 \le \frac{d + 2}{5} \cdot 5 \le \frac{6}{5} \cdot 5 $$

$$ -5 \le d + 2 \le 6 $$

Subtract 2 from all parts

$$ -5 - 2 \le d + 2 - 2 \le 6 - 2 $$

$$ -7 \le d \le 4 $$

Answer:

Solve the following compound inequality.

$$-1 \le \frac{d + 2}{5} \le \frac{6}{5}$$

<blank>-7</blank> \(\le d \le\) <blank>4</blank>