QUESTION IMAGE
Question
solve for b. express your answer as a proper or improper fraction in simplest terms.
$-\frac{1}{6} = \frac{1}{2}b + \frac{5}{6}$
Step1: Subtract 5/6 from both sides
To isolate the term with \( b \), we subtract \( \frac{5}{6} \) from both sides of the equation \( -\frac{1}{6} = \frac{1}{2}b + \frac{5}{6} \).
Simplifying the left side: \( -\frac{1 + 5}{6} = -\frac{6}{6} = -1 \), and the right side simplifies to \( \frac{1}{2}b \). So we have \( -1 = \frac{1}{2}b \).
Step2: Multiply both sides by 2
To solve for \( b \), we multiply both sides of the equation \( -1 = \frac{1}{2}b \) by 2.
Simplifying both sides: The left side is \( -2 \), and the right side simplifies to \( b \). So \( b = -2 \). But we can also express -2 as a fraction, \( -\frac{2}{1} \), or we can check the steps again for any miscalculations. Wait, let's re - do step 1:
Wait, \( -\frac{1}{6}-\frac{5}{6}=\frac{-1 - 5}{6}=\frac{-6}{6}=-1 \), that's correct. Then step 2: \( \frac{1}{2}b=-1 \), multiply both sides by 2: \( b=-2 \), which is \( -\frac{2}{1} \) or just -2. But let's do it using fractions throughout.
Starting over:
Given \( -\frac{1}{6}=\frac{1}{2}b+\frac{5}{6} \)
Subtract \( \frac{5}{6} \) from both sides:
\( -\frac{1}{6}-\frac{5}{6}=\frac{1}{2}b \)
\( \frac{-1 - 5}{6}=\frac{1}{2}b \)
\( \frac{-6}{6}=\frac{1}{2}b \)
\( - 1=\frac{1}{2}b \)
Multiply both sides by 2:
\( b=-2=-\frac{2}{1} \)
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\( b = -\frac{2}{1} \) (or \( b=-2 \))