Question

solve the equation. what is the value of h? now that there arent any parentheses on the left, lets think about getting the h term alone on that side. we can do that by moving all of the numbers to the right side. you can think of subtracting 12 as negative 12. what move could you make next to get rid of -12 on the left side, while keeping the equation balanced? 6(h - 2) = 12 6h - 12 = 12 multiply both sides by 12 add 12 to both sides subtract 12 from both sides

Explanation:

Step1: Analyze the equation

We have the equation \(6h - 12=12\). The left - hand side has a \(- 12\) term, and we want to isolate the term with \(h\) (i.e., \(6h\)).

Step2: Recall the addition property of equality

The addition property of equality states that if we add the same number to both sides of an equation, the equation remains balanced. To get rid of \(-12\) on the left - hand side, we need to add \(12\) to both sides because \(-12 + 12=0\).
If we add \(12\) to the left - hand side: \((6h-12)+12 = 6h+(- 12 + 12)=6h\)
If we add \(12\) to the right - hand side: \(12 + 12=24\)
So the operation we should perform is to add \(12\) to both sides.

Answer:

Add 12 to both sides