solve the equation to find a.

\10(a-5) = 6(a-3)\

\a = \underline{\quad}\

Question

solve the equation to find a.

\10(a-5) = 6(a-3)\

\a = \underline{\quad}\

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Linear Equations", "Algebraic Simplification" ], "new_concepts": [], "current_concepts": [ "Linear Equations", "Algebraic Simplification" ] } ## Expand both sides of the equation $$ \begin{aligned} 10(a - 5) &= 6(a - 3) \ 10a - 50 &= 6a - 18 \end{aligned} $$ ## Isolate the variable terms on one side $$ \begin{aligned} 10a - 6a &= -18 + 50 \ 4a &= 32 \end{aligned} $$ ## Solve for a $$ \begin{aligned} a &= \frac{32}{4} \ a &= 8 \end{aligned} $$ Solve the equation to find a. $10(a-5) = 6(a-3)$ $a =$ 8 { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Linear Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Expand both sides of the equation

Isolate the variable terms on one side

Solve for a

Answer: