Question

solve the equation $x^{2}-6x + 9 = 0$. a $x = 3$ b $x = 6$ c $x = 3$ or $x=-3$ d $x = 6$ or $x=-9$ e $x = 9$ or $x=-9$

Explanation:

Step1: Factor the quadratic equation

We know that \(x^{2}-6x + 9=(x - 3)^{2}\), so the equation \((x - 3)^{2}=0\).

Step2: Solve for x

If \((x - 3)^{2}=0\), then \(x-3 = 0\), and \(x=3\).

Answer:

A. \(x = 3\)