QUESTION IMAGE
Question
solve the equation.
\\e^{-6w-24} = e^{(3w-5)(w+4)}\\
\\(w =\\)
Step1: Equate the exponents
$$-6w - 24 = (3w - 5)(w + 4)$$
Step2: Expand the right side
$$-6w - 24 = 3w^2 + 12w - 5w - 20$$
Step3: Simplify the equation
$$-6w - 24 = 3w^2 + 7w - 20$$
Step4: Move all terms to one side
$$3w^2 + 13w + 4 = 0$$
Step5: Factor the quadratic equation
$$(3w + 1)(w + 4) = 0$$
Step6: Solve for \(w\)
$$w = -\frac{1}{3}, -4$$
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\(w = -4, \frac{1}{3}\)