Question

solve each equation.

1. $-3(b - 3) = 15$
2. $-5 + \frac{x}{2} = -7$
3. $-(b - 5) = 7$
4. $2(x + 4) = 12$
5. $2 + \frac{x}{10} = 3$

Explanation:

1) Step1: Divide both sides by -3

$\frac{-3(b-3)}{-3}=\frac{15}{-3}$
$b-3=-5$

1) Step2: Add 3 to both sides

$b-3+3=-5+3$
$b=-2$

3) Step1: Add 5 to both sides

$-5+\frac{x}{2}+5=-7+5$
$\frac{x}{2}=-2$

3) Step2: Multiply by 2 on both sides

$\frac{x}{2} \times 2=-2 \times 2$
$x=-4$

5) Step1: Distribute the negative sign

$-b+5=7$

5) Step2: Subtract 5 from both sides

$-b+5-5=7-5$
$-b=2$

5) Step3: Multiply by -1

$-b \times (-1)=2 \times (-1)$
$b=-2$

7) Step1: Divide both sides by 2

$\frac{2(x+4)}{2}=\frac{12}{2}$
$x+4=6$

7) Step2: Subtract 4 from both sides

$x+4-4=6-4$
$x=2$

9) Step1: Subtract 2 from both sides

$2+\frac{x}{10}-2=3-2$
$\frac{x}{10}=1$

9) Step2: Multiply by 10 on both sides

$\frac{x}{10} \times 10=1 \times 10$
$x=10$

Answer:

1. $b=-2$
2. $x=-4$
3. $b=-2$
4. $x=2$
5. $x=10$