Question

solve the compound inequality. 2x - 1 ≤ -1 or 3x + 2 ≥ 20 graph the solution on the number line.

Explanation:

Step1: Solve the first inequality

Add 1 to both sides of $2x - 1\leq - 1$.
$2x-1 + 1\leq - 1+1$
$2x\leq0$
Divide both sides by 2: $x\leq0$

Step2: Solve the second inequality

Subtract 2 from both sides of $3x + 2\geq20$.
$3x+2 - 2\geq20 - 2$
$3x\geq18$
Divide both sides by 3: $x\geq6$

Answer:

The solution of the compound - inequality is $x\leq0$ or $x\geq6$. On the number line, we draw a closed circle at 0 and shade to the left for $x\leq0$, and draw a closed circle at 6 and shade to the right for $x\geq6$.