Question

e solution of the system of equations.

$8x + y = -13$

$-8x - 2y = 10$

Explanation:

Step1: Add the two equations

Add the equations \(8x + y = -13\) and \(-8x - 2y = 10\) together.

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Step2: Solve for y

Multiply both sides of \(-y = -3\) by \(-1\) to get \(y\).

$$y = 3$$

Step3: Substitute y into first equation

Substitute \(y = 3\) into \(8x + y = -13\).

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Step4: Solve for x

Divide both sides of \(8x = -16\) by \(8\).

$$x = \frac{-16}{8} = -2$$

Answer:

The solution is \(x = -2\), \(y = 3\)