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$-x + 4y = 4$ $-x + 3y = 1$ is $(8, 3)$ a solution of the system? choos…

Question

$-x + 4y = 4$

$-x + 3y = 1$

is $(8, 3)$ a solution of the system?

choose 1 answer:

a yes

b no

show calculator

Explanation:

Step1: Check first equation

Substitute \(x = 8\), \(y = 3\) into \(-x + 4y = 4\).
Left - hand side (LHS) \(=-8 + 4\times3=-8 + 12 = 4\).
Right - hand side (RHS) \(= 4\). So, LHS = RHS for the first equation.

Step2: Check second equation

Substitute \(x = 8\), \(y = 3\) into \(-x+3y = 1\).
Left - hand side (LHS) \(=-8 + 3\times3=-8 + 9 = 1\).
Right - hand side (RHS) \(= 1\). So, LHS = RHS for the second equation.

Since \((8,3)\) satisfies both equations in the system, it is a solution.

Answer:

A. Yes