Question

a slingshot projects 170 g water balloons horizontally off a two - story roof 5.5 m off the ground with an initial velocity of 24 m/s. what is the range of each water balloon? (1 point)
1.06 s
there is not enough information to determine the range of the water balloons.
1,666 m/s²
25.44 m

Explanation:

Step1: Calculate the time of flight

Use the vertical motion equation \(h = v_{0y}t+\frac{1}{2}gt^{2}\). Since the balloon is projected horizontally, \(v_{0y} = 0\). The equation becomes \(h=\frac{1}{2}gt^{2}\), where \(h = 5.5\space m\) and \(g=9.8\space m/s^{2}\).

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Step2: Calculate the range

The range \(R\) (horizontal distance) is given by \(R = v_{0x}t\), where \(v_{0x}=24\space m/s\) and \(t = 1.06\space s\) (from Step 1).

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Answer:

25.44 m