Question

simplify.

$(v^{-2})^{-7}$

write your answer without using negative exponents.

Explanation:

Step1: Apply exponent rule \((a^m)^n = a^{m\times n}\)

For \((v^{-2})^{-7}\), we multiply the exponents: \(-2\times(-7)=14\). So we get \(v^{14}\).

Answer:

\(v^{14}\)