QUESTION IMAGE
Question
simplify the expression to solve the equation.\
x = \square\
done\
2±√(12² - 4(4)(9))/(2(4))\
-12±√(12² + 4(4)(9))/(2(4))\
chat with a tutor\
²+12x+9.\
equation that shows the correct\
of a, b, and c in the quadratic formula.
Step1: Calculate the discriminant
First, calculate the value inside the square root: \(12^2 - 4(4)(9)\).
\(12^2 = 144\), \(4(4)(9)=144\), so \(144 - 144 = 0\).
Step2: Simplify the numerator
The numerator becomes \(-12 \pm \sqrt{0}\) (assuming the quadratic is \(4x^2 + 12x + 9 = 0\), so \(a = 4\), \(b = 12\), \(c = 9\), and the quadratic formula is \(x=\frac{-b\pm\sqrt{b^2 - 4ac}}{2a}\), so the numerator should be \(-12 \pm \sqrt{12^2 - 4(4)(9)}\)). Since \(\sqrt{0}=0\), the numerator is \(-12\).
Step3: Simplify the denominator
The denominator is \(2(4)=8\).
Step4: Solve for x
Now, \(x=\frac{-12}{8}\), which simplifies to \(x = -\frac{3}{2}\).
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\(x = -\frac{3}{2}\)