Question

simplify the expression below using order of operations.
$1 + \frac{(3^2 - 3^2)}{2}$

Explanation:

Step1: Calculate exponents in numerator

First, we calculate the exponents in the numerator of the fraction. For \(3^2\), we know that \(3^2 = 3\times3 = 9\). So the expression inside the parentheses becomes \(9 - 9\).

$$3^2 - 3^2 = 9 - 9$$

Step2: Simplify the numerator

Now, we simplify the numerator of the fraction. \(9 - 9 = 0\). So the fraction \(\frac{3^2 - 3^2}{2}\) becomes \(\frac{0}{2}\).

$$\frac{3^2 - 3^2}{2}=\frac{9 - 9}{2}=\frac{0}{2}$$

Step3: Simplify the fraction

Next, we simplify the fraction \(\frac{0}{2}\). Any number divided by 2 (except 0) has a certain value, but 0 divided by any non - zero number is 0. So \(\frac{0}{2}=0\).

Step4: Add 1 to the result of the fraction

Finally, we add 1 to the result of the fraction. We have \(1+0\).

$$1+\frac{0}{2}=1 + 0$$

Answer:

\(1\)