Question

simplify the expression.
\\(\frac{1}{3}(-15x + 9) = \frac{1}{3}(-15x) + \frac{1}{3}(9)\\)
\\(= square x + ?\\)

Explanation:

Step1: Multiply $\frac{1}{3}$ by $-15x$

$\frac{1}{3}(-15x) = \frac{-15x}{3} = -5x$

Step2: Multiply $\frac{1}{3}$ by $9$

$\frac{1}{3}(9) = \frac{9}{3} = 3$

Step3: Combine the results

$-5x + 3$

Answer:

$-5x + 3$